What is the equation of a line that passes through the points (-2, 5) and (3, -1)? Here we will show you how to find the equation of a line that passes through the points (-2, 5) and (3, -1).
Linear equations can be expressed in various forms. On this page, we will be finding the equation of a line that passes through the points (x1, y1) and (x2, y2) in standard form, which is written as Ax + By + C = 0. Here are the formulas and the math used to convert points (-2, 5) and (3, -1) into an equation in standard form:
(x1, y1) and (x2, y2)
(-2, 5) and (3, -1)
A = y2 - y1
A = -1 - 5
A = -6
B = x1 - x2
B = -2 - 3
B = -5
C = y1 × (x2 - x1) - (y2 - y1) × x1
C = 5 × (3 - -2) - (-1 - 5) × -2
C = 13
And when we put it all together, we get the equation of a line that passes through the points (-2, 5) and (3, -1), as seen below:
Ax + By + C = 0
-6x - 5y + 13 = 0
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Equation of a line that passes through the points (-2, 5) and (3, 0)?
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