What is the equation of a line that passes through the points (-2, 5) and (4, 6)? Here we will show you how to find the equation of a line that passes through the points (-2, 5) and (4, 6).
Linear equations can be expressed in various forms. On this page, we will be finding the equation of a line that passes through the points (x1, y1) and (x2, y2) in standard form, which is written as Ax + By + C = 0. Here are the formulas and the math used to convert points (-2, 5) and (4, 6) into an equation in standard form:
(x1, y1) and (x2, y2)
(-2, 5) and (4, 6)
A = y2 - y1
A = 6 - 5
A = 1
B = x1 - x2
B = -2 - 4
B = -6
C = y1 × (x2 - x1) - (y2 - y1) × x1
C = 5 × (4 - -2) - (6 - 5) × -2
C = 32
And when we put it all together, we get the equation of a line that passes through the points (-2, 5) and (4, 6), as seen below:
Ax + By + C = 0
1x - 6y + 32 = 0
x - 6y + 32 = 0
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