What is the equation of a line that passes through the points (-3, 4) and (2, 8)? Here we will show you how to find the equation of a line that passes through the points (-3, 4) and (2, 8).
Linear equations can be expressed in various forms. On this page, we will be finding the equation of a line that passes through the points (x1, y1) and (x2, y2) in standard form, which is written as Ax + By + C = 0. Here are the formulas and the math used to convert points (-3, 4) and (2, 8) into an equation in standard form:
(x1, y1) and (x2, y2)
(-3, 4) and (2, 8)
A = y2 - y1
A = 8 - 4
A = 4
B = x1 - x2
B = -3 - 2
B = -5
C = y1 × (x2 - x1) - (y2 - y1) × x1
C = 4 × (2 - -3) - (8 - 4) × -3
C = 32
And when we put it all together, we get the equation of a line that passes through the points (-3, 4) and (2, 8), as seen below:
Ax + By + C = 0
4x - 5y + 32 = 0
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