What is the equation of a line that passes through the points (-5, 8) and (3, -7)? Here we will show you how to find the equation of a line that passes through the points (-5, 8) and (3, -7).
Linear equations can be expressed in various forms. On this page, we will be finding the equation of a line that passes through the points (x1, y1) and (x2, y2) in standard form, which is written as Ax + By + C = 0. Here are the formulas and the math used to convert points (-5, 8) and (3, -7) into an equation in standard form:
(x1, y1) and (x2, y2)
(-5, 8) and (3, -7)
A = y2 - y1
A = -7 - 8
A = -15
B = x1 - x2
B = -5 - 3
B = -8
C = y1 × (x2 - x1) - (y2 - y1) × x1
C = 8 × (3 - -5) - (-7 - 8) × -5
C = -11
And when we put it all together, we get the equation of a line that passes through the points (-5, 8) and (3, -7), as seen below:
Ax + By + C = 0
-15x - 8y - 11 = 0
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