What is the equation of a line that passes through the points (-5, 8) and (4, -4)? Here we will show you how to find the equation of a line that passes through the points (-5, 8) and (4, -4).
Linear equations can be expressed in various forms. On this page, we will be finding the equation of a line that passes through the points (x1, y1) and (x2, y2) in standard form, which is written as Ax + By + C = 0. Here are the formulas and the math used to convert points (-5, 8) and (4, -4) into an equation in standard form:
(x1, y1) and (x2, y2)
(-5, 8) and (4, -4)
A = y2 - y1
A = -4 - 8
A = -12
B = x1 - x2
B = -5 - 4
B = -9
C = y1 × (x2 - x1) - (y2 - y1) × x1
C = 8 × (4 - -5) - (-4 - 8) × -5
C = 12
And when we put it all together, we get the equation of a line that passes through the points (-5, 8) and (4, -4), as seen below:
Ax + By + C = 0
-12x - 9y + 12 = 0
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