What is the equation of a line that passes through the points (1, 6) and (4, -5)? Here we will show you how to find the equation of a line that passes through the points (1, 6) and (4, -5).
Linear equations can be expressed in various forms. On this page, we will be finding the equation of a line that passes through the points (x1, y1) and (x2, y2) in standard form, which is written as Ax + By + C = 0. Here are the formulas and the math used to convert points (1, 6) and (4, -5) into an equation in standard form:
(x1, y1) and (x2, y2)
(1, 6) and (4, -5)
A = y2 - y1
A = -5 - 6
A = -11
B = x1 - x2
B = 1 - 4
B = -3
C = y1 × (x2 - x1) - (y2 - y1) × x1
C = 6 × (4 - 1) - (-5 - 6) × 1
C = 29
And when we put it all together, we get the equation of a line that passes through the points (1, 6) and (4, -5), as seen below:
Ax + By + C = 0
-11x - 3y + 29 = 0
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Equation of a line that passes through the points (1, 6) and (4, -4)?
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