Here we will show you how to find the equation of a line that is perpendicular to y = -3x + 7.
First of all, the equation y = -3x + 7 creates a straight line on a graph, and the equation of a line that is perpendicular to y = -3x + 7 creates a line that crosses y = -3x + 7 to create a 90-degree angle. In other words, the two equations make a perfect cross.
Furthermore, the slope of a line that is perpendicular to y = -3x + 7 is the negative inverse of the slope of y = -3x + 7.
The slope of y = -3x + 7 is -3, and the negative inverse of of -3 is approximately 0.333333. Therefore, we can start by writing the equation of a line that is perpendicular to y = -3x + 7 like this:
y ≈ 0.333333x + b
To find b in the equation above, we need to know a point on the perpendicular line. For example, if we know the perpendicular line passes through the point (1,2), where x = 1 and y = 2, then all we have to do is enter these values into the formula and solve for b, like this:
y ≈ 0.333333x + b
2 ≈ (0.333333)1 + b
b ≈ 1.666667
Therefore, the equation of a line that is perpendicular to y = -3x + 7 and travels through point (1,2) is as follows:
y ≈ 0.333333x + 1.666667
To calculate b for another point, please enter it below so we can calculate it for you:
Perpendicular Equation Calculator
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